Interior angles

In a quadrilateral ABCD, whose vertices lie on some circle, the angle at vertex A is 58 degrees and the angle at vertex B is 134 degrees. Calculate the sizes of the remaining interior angles.

Correct answer:

C =  122 °
D =  46 °

Step-by-step explanation:

A=58 ° B=134 °  2DCB=DSB1 2DAB=DSB2 DSB1+DSB2=360° 2DCB+2DAB=360° DCB+DAB=180° C+A=180°  A+C=180°  C=180A=18058=122°
B+D=180°  D=180B=180134=46°



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