Interior angles

In a quadrilateral ABCD, whose vertices lie on some circle, the angle at vertex A is 58 degrees, and the angle at vertex B is 134 degrees. Calculate the sizes of the remaining interior angles.

Correct answer:

C =  122 °
D =  46 °

Step-by-step explanation:

A=58  B=134    2DCB = DSB1  2DAB = DSB2  DSB1 + DSB2 = 360°  2DCB + 2DAB = 360°  DCB + DAB = 180° C+A = 180°  A+C = 180°  C=180A=18058=122
B+D = 180°  D=180B=180134=46

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