Interior angles

In a quadrilateral ABCD, whose vertices lie on some circle, the angle at vertex A is 58 degrees and the angle at vertex B is 134 degrees. Calculate the sizes of the remaining interior angles.

Correct result:

C =  122 °
D =  46 °

Solution:

A=58 B=134  2DCB=DSB1 2DAB=DSB2 DSB1+DSB2=360 2DCB+2DAB=360 DCB+DAB=180 C+A=180  A+C=180  C=180A=18058=122
B+D=180  D=180B=180134=46



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