Quadrilateral angle circle

The points ABC lie on the circle k(S, r) such that the angle at B is obtuse. How large must the angle at vertex B of quadrilateral SCBA be so that this angle is three times greater than the interior angle ASC of the same quadrilateral?

Final Answer:

B =  154.2857 °

Step-by-step explanation:

SCBA B = α + β  α+β = 3 (3602α2β) 7 α + 7 β  1080 = 0  α + β = 1080/7  B=1080/7=154.2857=154°179"



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geometryplanimetricsUnits of physical quantitiesGrade of the word problem

 
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