If John has a running speed of 3.5miles per hour and Lucy has a speed of 5 miles per hour. If John starts running at 10:00 AM, and Lucy starts running at 10:30 AM, what time will they meet? (as soon as possible)


t = 11:40 hh:mm Wrong answer

Step-by-step explanation:

v1=3.5 mph v2=5 mph t2=10+30/60=221=10.5 h  s1 = s2  v1 (t10.00)=v2 (tt2) 3.5 (t10.00)=5 (t10.5)  1.5t=17.5  t=1.517.5=11.66666667  t=33511.666667=11.66667=11:40 hh:mm

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