One green

In the container are 45 white and 15 green balls. We randomly select five balls. What is the probability that there will be one green ball maximally?

Correct answer:

p =  0.6329

Step-by-step explanation:

C5(60)=(560)=5!(605)!60!=543216059585756=5461512 C0(15)=(015)=0!(150)!15!=11=1  C5(45)=(545)=5!(455)!45!=543214544434241=1221759  C1(15)=(115)=1!(151)!15!=115=15  C4(45)=(445)=4!(454)!45!=432145444342=148995  a=(015) (545)+(115) (445)=1 1221759+15 148995=3456684 b=(545+15)=5461512  p=ba=54615123456684=0.6329

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