The probability that the bulb can operate 4000 hours is 0.3. What is the probability that exactly one of the eight bulbs can operate 4000 hours?

Correct answer:

p2 =  19.8 %

Step-by-step explanation:

p=0.3  C1(8)=(18)=1!(81)!8!=18=8  p2=100 (18) p (1p)81=100 8 0.3 (10.3)81=19.8%

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