# The confectionery

The confectionery sold 5 kinds of ice cream. In how many ways can I buy 3 kinds if order of ice creams does not matter?

Result

n =  10

#### Solution:

$C_{{ 3}}(5)=\dbinom{ 5}{ 3}=\dfrac{ 5! }{ 3!(5-3)!}=\dfrac{ 5 \cdot 4 } { 2 \cdot 1 }=10 \ \\ \ \\ n={ { 5 } \choose 3 }=10$

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