Perimeter and legs

Determine the perimeter of a right triangle if the length of one leg is 75% length of the second leg and its content area is 24 cm2.

Correct result:

x =  24

Solution:

S=ab/2=24 2⋅24=0.75a2 a=2⋅24/0.75=8 cm b=0.75a=6 cm c2=a2+b2 c=a2+b2=10 cm x=a+b+c=8+6+10=24

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