Leg

Determine the area of a trapezoid with bases 71 and 42 and height is 4 shorter than the its leg.

Result

S =  1371.89

Solution:

h=r4 r2=h2+((ac)/2)2 h2+2h4+42=h2+((7142)/2)2 h=24.28  S=a+c2h=71+42224.28=1371.89h = r-4 \ \\ r^2=h^2+((a-c)/2)^2 \ \\ h^2+2h\cdot 4 + 4^2 = h^2 + ((71-42)/2)^2 \ \\ h = 24.28 \ \\ \ \\ S = \dfrac{ a+c}{2} h = \dfrac{ 71+42 }{2} \cdot 24.28 = 1371.89



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