Rotary cylinder 2

Base circumference of the rotary cylinder has same length as its height. What is the surface area of cylinder if its volume is 250 dm³?

Correct result:

S =  248.64 dm²

Solution:

$$\begin{gathered} h=2\pi r \\ V=\pi r^{2}h=\pi r^2\cdot 2\pi r=2\cdot p{i}^2{r}^3=250 \\ r=\sqrt[3]{{\displaystyle \frac{V}{2{\pi }^2}}}=2.33dm \\ h=2\pi r=14.65dm \\ S=2\pi r^2+2\pi rh=248.64{\text{dm}}^2 \end{gathered}$$

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