Win in raffle

The raffle tickets were sold to 200, 5 of which were winning. What is the probability that Peter, who bought one ticket, will win?

Correct answer:

p =  2.5254 %

Step-by-step explanation:

p=100 (2001+1991+1981+1971+1961)=2.5254%

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Showing 1 comment:
Dr Math
The answer rounds down to 2.5%, but it is actually 2.5253. That's because Peter gets 5 chances at the ticket, but with a reducing denominator. 1/200 + 1/199 + 1/198 + 1/197 + 1/196. This makes a big difference if there were only 10 tickets sold. With the math published, the result would be 50%. But it's far higher of a chance. It is actually: 64.5%

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