Medians in RT

The rectangular triangle ABC has a length of 10 cm and 24 cm. Points P, Q, R are the centers of the sides of this triangle. The perimeter of the PQR triangle is:

Result

o =  30 cm

Solution:

a=10 cm b=24 cm  c=a2+b2=102+242=26 cm o=a+b+c2=10+24+262=30 cma=10 \ \text{cm} \ \\ b=24 \ \text{cm} \ \\ \ \\ c=\sqrt{ a^2+b^2 }=\sqrt{ 10^2+24^2 }=26 \ \text{cm} \ \\ o=\dfrac{ a+b+c }{ 2 }=\dfrac{ 10+24+26 }{ 2 }=30 \ \text{cm}

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