Medians in RT

The rectangular triangle ABC has a length of 10 cm and 24 cm. Points P, Q, R are the centers of the sides of this triangle. The perimeter of the PQR triangle is:

Correct result:

o =  30 cm

Solution:

$$\begin{gathered} a=10\text{ cm } \\ b=24\text{ cm } \\ c=\sqrt{a^2+b^2}=\sqrt{10^2+24^2}=26\text{ cm } \\ o={\displaystyle \frac{a+b+c}{2}}={\displaystyle \frac{10+24+26}{2}}=30\text{ cm} \end{gathered}$$

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