Drink coconut percentage

The mixed drink consists of 1.5 dcl of pineapple juice and 0.5 dcl of coconut syrup. Klára ordered it sweeter, so the bartender changed the volume of coconut syrup to a ratio of 3:2. What percent of the drink is now coconut syrup if the volume of the juice has not changed?

Final Answer:

p =  33.3333 %

Step-by-step explanation:

$$\begin{gathered} V_1=1.5\text{dcl} \\ {V}_2=0.5\text{dcl} \\ {V}_3=V_2\cdot 3/2=0.5\cdot 3/2=\frac{3}{4}=0.75\text{dcl} \\ p=100\cdot \frac{V_3}{V_3+V_1}=100\cdot \frac{0.75}{0.75+1.5}=\frac{100}{3}\%=33.3333\% \end{gathered}$$

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