Concentration

We try 0.5 liters of 8% vinegar dilute to a concentration of 20 hundredths % of vinegar. How many liters of water must we add?

Final Answer:

V2 =  19.5 l

Step-by-step explanation:

r1=8%=1008=252=0.08 V1=1/2=21=0.5 l  r2=10020/100=100 10020=1000020=5001=0.002  V1 r1=r2 (V2+V1) 0.5 0.08=0.002 (V2+0.5)  0.002V2=0.039  V2=0.0020.039=19.5  V2=239=19.5=19.5 l



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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesthemes, topicsGrade of the word problem

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