We must dilute 16 liters of 8.8% aqueous vinegar to 4.1% one. How much water is necessary to add?

Correct answer:

V =  18.3 l

Step-by-step explanation:

8.8/100 • 16 = (V + 16) • 4.1/100

4.1V = 75.2

V = 752/41 ≈ 18.341463

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