Difference of legs

In a right triangle, the length of the hypotenuse is 65 m, and the difference of legs is 23 m. Calculate the perimeter of this triangle.

Correct result:

o =  154 m


c=65 m a=b+23 m c2=a2+b2  652=(b+23)2+b2  652=(b+23)2+b2  2b246b+3696=0 2b2+46b3696=0  p=2;q=46;r=3696 D=q24pr=46242(3696)=31684 D>0  b1,2=q±D2p=46±316844 b1,2=46±1784 b1,2=11.5±44.5 b1=33 b2=56   Factored form of the equation:  2(b33)(b+56)=0  b>0 b=b1=33=33 m a=b+23=33+23=56 m  o=a+b+c=56+33+65=154 m

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