# Euklid4

Legs of a right triangle have dimensions 244 m and 246 m. Calculate the length of the hypotenuse and the height of this right triangle.

Result

c =  346.49 m
h =  173.24 m

#### Solution:

$c^2 = a^2 + b^2 \ \\ c^2 = 244^2 + 246^2 \ \\ c = \sqrt{ 120052 } = 346.49 \ \text{m}$
$S = \dfrac{ab}{2} = \dfrac{ch}{2} \ \\ ab = ch \ \\ h = \dfrac{ab}{c} = \dfrac{ 244 \cdot 246}{ 346.485 } = 173.24 \ \text{m}$

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