Cone roof

How many m2 of roofing is needed to cover a cone-shaped roof with a diameter of 10 m and a height of 4 m? Add an extra 4% to the overlays.

Correct result:

S =  104.6032 m2

Solution:

D=10 m h=4 m q=4%=1+4100=1.04  r=D/2=10/2=5 m s=h2+r2=42+52=41 m≐6.4031 m  S1=π⋅ r⋅ s=3.1416⋅ 5⋅ 6.4031≐100.58 m2  S=q⋅ S1=1.04⋅ 100.58=104.6032 m2

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