# Parallelogram

In the parallelogram we know one internal angle 67°33`. Calculate the other internal angles.

β =  112.45 °
γ =  67.55 °
δ =  112.45 °

### Step-by-step explanation:

$\beta =180-\left(67+33\mathrm{/}60\right)=112.45\text{°}=112\mathrm{°}2{7}^{\mathrm{\prime }}$
$\gamma =67+33\mathrm{/}60=67.55\text{°}=67\mathrm{°}3{3}^{\mathrm{\prime }}$
$\delta =180-\left(67+33\mathrm{/}60\right)=112.45\text{°}=112\mathrm{°}2{7}^{\mathrm{\prime }}$

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