The farmer

The farmer calculated that the supply of fodder for his 20 cows was enough for 60 days. He decided to sell 2 cows and a third of the feed. How long will the feed for the rest of the peasant's herd last?

Correct answer:

t =  44.4444 d

Step-by-step explanation:

$$\begin{gathered} n=20 \\ d=60 \\ n\cdot d-n\cdot d\mathrm{/}3=t\cdot (n-2) \\ 20\cdot 60-20\cdot 60\mathrm{/}3=t\cdot (20-2) \\ 54t=2400 \\ t={\displaystyle \frac{400}{9}}\doteq 44.444444=44.4444\text{ d} \end{gathered}$$

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