Cinema 4

In cinema are 1656 seats and in the last row are 105 seats , in each next row 3 seats less. How many are the total rows in cinema?

Correct result:

n =  23

Solution:

1. a(1) = 105; S(1) = 105
2. a(2) = 102; S(2) = 207
3. a(3) = 99; S(3) = 306
4. a(4) = 96; S(4) = 402
5. a(5) = 93; S(5) = 495
6. a(6) = 90; S(6) = 585
7. a(7) = 87; S(7) = 672
8. a(8) = 84; S(8) = 756
9. a(9) = 81; S(9) = 837
10. a(10) = 78; S(10) = 915
11. a(11) = 75; S(11) = 990
12. a(12) = 72; S(12) = 1062
13. a(13) = 69; S(13) = 1131
14. a(14) = 66; S(14) = 1197
15. a(15) = 63; S(15) = 1260
16. a(16) = 60; S(16) = 1320
17. a(17) = 57; S(17) = 1377
18. a(18) = 54; S(18) = 1431
19. a(19) = 51; S(19) = 1482
20. a(20) = 48; S(20) = 1530
21. a(21) = 45; S(21) = 1575
22. a(22) = 42; S(22) = 1617
23. a(23) = 39; S(23) = 1656

$$\begin{gathered} s_n=1656 \\ {a}_1=105 \\ d=-3 \\ {s}_n=n(a_1+a_n)\mathrm{/}2=n(a_1+a_1+(n-1)d)\mathrm{/}2 \\ 1656=n\mathrm{/}2(2\cdot 105-3\cdot (n-1)) \\ 3312=n(213-3n) \\ 3312=213n-3n^2 \\ 3n^2-213n+3312=0 \\ {n}_{1,2}={\displaystyle \frac{-b\pm \sqrt{D}}{2a}}={\displaystyle \frac{213\pm \sqrt{5625}}{6}} \\ {n}_{1,2}={\displaystyle \frac{213\pm 75}{6}} \\ {n}_{1,2}=35.5\pm 12.5 \\ {n}_1=48 \\ {n}_2=23 \\ n=23 \end{gathered}$$

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