Calculate the edge of the cube made ​​from lead, which weighs 19 kg. The density of lead is 11341 kg/m3.

Result

a =  11.9 cm

#### Solution:

$a = \sqrt[3]{\dfrac{ m}{ \rho} } = 100 \sqrt[3]{\dfrac{ 19}{ 11341} } = 11.9 \ \text{ cm }$

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