Telegraph poles

The bases of two adjacent telegraph poles have a height difference of 10.5 m. How long do the wires connect the two poles if the slope is 39° 30´?

Correct answer:

x =  16.5074 m

Step-by-step explanation:

$$\begin{gathered} h=10.5\text{ m } \\ A=39+30\mathrm{/}60={\displaystyle \frac{79}{2}}=39.5^{\circ } \\ \sin A=h:x \\ x=h\mathrm{/}\sin A^{\circ }=h\mathrm{/}\sin 39.5^{\circ }=10.5\mathrm{/}\sin 39.5^{\circ }=10.5\mathrm{/}0.636078=16.507=16.5074\text{ m} \end{gathered}$$

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