# Clock

How long is trajectory of second hand of hours for day, if is 15 mm long?

Result

l =  135.7 m

#### Solution:

$r = 15 \ mm = 15 / 1000 \ m = 0.015 \ m \ \\ o = 2 \pi \cdot \ r = 2 \cdot \ 3.1416 \cdot \ 0.015 \doteq 0.0942 \ m \ \\ n = 1 \cdot \ 24 \cdot \ 60 = 1440 \ \\ l = n \cdot \ o = 1440 \cdot \ 0.0942 \doteq 135.7168 = 135.7 \ \text{ m }$

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