In the

In the rectangle ABCD, the distance of its center from the line AB is 3 cm greater than from the line BC. The circumference of the rectangle is 52 cm. Calculate the contents of the rectangle. Express the result in cm2.

Correct result:

S =  160 cm2

Solution:

o=52 cm   o=2 (a+b) b/2=3+a/2 52=2 (a+b) b/2=3+a/2  2a+2b=52 ab=6  a=10 b=16   S=a b=10 16=160 cm2



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