Distance of the parallels

Find the distance of the parallels, which equations are:
x = 3-4t, y = 2 + t and x = -4t, y = 1 + t
(instructions: select a point on one line and find its distance from the other line)

Correct answer:

x =  1.6977

Step-by-step explanation:

p1: x=34t, y=2+t p2: x=4t, y=1+t A1 = 3 A2 = 2 A[3,2]  p2: x+4y  4 = 0 N=12+42=174.1231 x=(1 3+4 24)/N=(1 3+4 24)/4.1231=1.6977



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Showing 1 comment:
Math student
Using a ruler a pair of compasses only construct triangle ABC in which AB=5cm BC=5.9cm and<BAC=45°





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