Parametric form

Calculate the distance of point A [2,1] from the line p:
X = -1 + 3 t
Y = 5-4 t
Line p has a parametric form of the line equation. ..

Correct result:

x =  0.2

Solution:

p: x=−1+3t y=5−4t  A[2,1]=A[m,n] m=2 n=1  q⊥p:ax+by+c=0 a=4 b=3 q:4x+3y+c=0   4⋅ (−1)+3⋅ 5+c=0  c=−11   x=∣a⋅ m+a⋅ n+c∣a2+b2=∣4⋅ 2+4⋅ 1+(−11)∣42+32=15=0.2

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