Determine 82478

Determine the equation of the parabola that has the point F = [3,2] as its focus and the line x+y+1=0 as its shift line.

Correct answer:

p : 25 - 14 x + x^2 - 10 y - 2 x y + y^2 = 0

Step-by-step explanation:

F=(3,2) r:x+y+1=0 n=(1,1) nr  v1 = v2 v1 = (xFx)2+(yFy)2 v2 =  nx2+ny2nx x+ny y+1  2   ((xFx)2+(yFy)2) = (nx x+ny y+1)2 2  (x3)2 + (y2)2) = (x+y+1)2  p:2514 x+x210 y2 xy+y2=0

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