Determine 82478

Determine the equation of the parabola that has the point F = [3,2] as its focus and the line x+y+1=0 as its shift line.

Correct answer:

p : 25 - 14 x + x^2 - 10 y - 2 x y + y^2 = 0

Step-by-step explanation:

F=(3,2) r:x+y+1=0 n=(1,1) n⊥r  v1​ = v2​ v1​ = (x−Fx​)2+(y−Fy​)2​ v2​ =  nx2​+ny2​​∣nx​⋅ x+ny​⋅ y+1∣​  2 ⋅  ((x−Fx​)2+(y−Fy​)2) = (nx​⋅ x+ny​⋅ y+1)2 2 ⋅ (x−3)2 + (y−2)2) = (x+y+1)2  p:25−14 x+x2−10 y−2 xy+y2=0

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You need to know the following knowledge to solve this word math problem:

geometryalgebraarithmeticplanimetricsnumbersUnits of physical quantitiesGrade of the word problem

 
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