Circle - analytics geometry

Write the equation of the circle that passes through the points Q[3.5] R[2.6] and has its center on the line 2x+3y-4=0.

Correct answer:

e : (x+1)^2+(y-2)^2=25

Step-by-step explanation:

Q=(3,5) R=(2,6)  p: 2x+3y4=0 p: y = (42x)/3  S=(x0,y0)  SQ=SR=r SQ2=SR2=r2  (xQx)2+((42 x)/3Qy)2=(xRx)2+((42 x)/3Ry)2 (x3)2+((42 x)/35)2=(x2)2+((42 x)/36)2  10x=10  x=1010=1  x=1  x0=x=(1)=1 y0=(42 x)/3=(42 (1))/3=2  S=(1,2) r=(x0Qx)2+(y0Qy)2=((1)3)2+(25)2=5  e: (xx0)2+(yy0)2=r2  e:(x+1)2+(y2)2=25



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