Determine 82394

Determine the equation of the circle that passes through the point M(-1,2) and N( 3,0) and whose center lies on the line p: x=-3+t, y=-1+t,

Correct answer:

e : (x-3)^2+(y-5)^2=25

Step-by-step explanation:

M=(1,2) N=(3,0)  p: x=3+t, y=1+t  S=(x0,y0)  SN=SM=r SN2=SM2=r2  ((3+t)Mx)2+((1+t)My)2=((3+t)Nx)2+((1+t)Ny)2 ((3+t)(1))2+((1+t)2)2=((3+t)3)2+((1+t)0)2  4t=24  t=424=6  t=6  x0=3+t=3+6=3 y0=1+t=1+6=5  r=(x0Mx)2+(y0My)2=(3(1))2+(52)2=5  e: (xx0)2+(yy0)2=r2  e:(x3)2+(y5)2=25

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