Circle

Write the equation of a circle that passes through the point [0,6] and touches the X-axis point [5,0]:

(xxS)2+(yyS)2=r2

Final Answer:

xS =  5
yS =  5.08
r =  5.08

Step-by-step explanation:

S[xS;yS]=?;r=? xS=5 yS=r  (05)2+(6yS)2=r2=yS2 yS=2652+62=5.08 r=5.08  (x5)2+(y5.08)2=5.082
r=(5 5+6 6)/(2 6)=5.08



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