Rectangular trapezoid

The rectangular trapezoid ABCD is: /AB/ = /BC/ = /AC/. The length of the median is 6 cm. Calculate the circumference and area of a trapezoid.

Correct answer:

o =  26.9282 cm
S =  41.5692 cm²

Step-by-step explanation:

$$\begin{gathered} s=6 \\ s=(a+c)\mathrm{/}2 \\ c=a\mathrm{/}2 \\ 6=(a+a\mathrm{/}2)\mathrm{/}2 \\ a=12\mathrm{/}(1+1\mathrm{/}2)=8 \\ b=a=8 \\ c=a\mathrm{/}2=8\mathrm{/}2=4 \\ d=\sqrt{a^2-(a\mathrm{/}2{)}^2}=\sqrt{8^2-(8\mathrm{/}2{)}^2}=4\sqrt{3}\doteq 6.9282 \\ o=a+a+c+d=8+8+4+6.9282=26.9282\text{ cm} \end{gathered}$$

$S=d\cdot s=6.9282\cdot 6=24\sqrt{3}=41.5692{\text{cm}}^2$

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