Triangle SSS

Calculate perimeter and area of ​​a triangle ABC, if a=53, b=46 and c=40.

Correct answer:

p =  139
T =  891.619

Step-by-step explanation:

$$\begin{gathered} a=53 \\ b=46 \\ c=40 \\ p=a+b+c=53+46+40=139 \end{gathered}$$

$$\begin{gathered} s=p\mathrm{/}2=139\mathrm{/}2={\displaystyle \frac{139}{2}}=69\frac{1}{2}=69.5 \\ T=\sqrt{s\cdot (s-a)\cdot (s-b)\cdot (s-c)}=\sqrt{69.5\cdot (69.5-53)\cdot (69.5-46)\cdot (69.5-40)}=891.619 \end{gathered}$$

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