# Triangle from median

Calculate the perimeter, content, and magnitudes of the remaining angles of triangle ABC, given: a = 8.4; β = 105° 35 '; and median ta = 12.5.

Correct result:

A =  31.986 °
C =  42.43 °
o =  34.374
S =  43.284

#### Solution:

$A=31.986=31.98{6}^{\circ }=3{1}^{\circ }5{9}^{\mathrm{\prime }}10\mathrm{"}$
$C=42.43=\frac{4243}{100}={\frac{4243}{100}}^{\circ }=42.4{3}^{\circ }=4{2}^{\circ }2{5}^{\mathrm{\prime }}48\mathrm{"}$
$o=34.374$
$S=43.284$

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