Median

In triangle ABC is given side a=10 cm and median ta= 13 cm and angle gamma 90°.

Calculate length of the median tb.

Correct result:

tb =  11.66 cm

Solution:

$$\begin{gathered} b^2=t_a^2-(a\mathrm{/}2{)}^2 \\ b=\sqrt{13^2-(10\mathrm{/}2{)}^2}=12cm \\ {t}_b^2=a^2+(b\mathrm{/}2{)}^2 \\ {t}_b=\sqrt{10^2+(12\mathrm{/}2{)}^2}=11.66\text{ cm} \end{gathered}$$

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