Intervals 27081

Three lines depart from the bus terminal at 5:30 in the morning. At what time will all three buses meet again at the terminus first, if one has intervals of 10 minutes, the second 12 minutes, and the third 15 minutes?

Result

t = 6:30 Wrong answer

Step-by-step explanation:

t1=hour(5,30)=5.5 10=25 12=223 15=35 LCM(10,12,15)=2235=60  T=LCM(10,12,15)=60 min  t=t1+T/60=5.5+60/60=213=6.5=6:30



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Showing 1 comment:
Shells52
This problem is very confusing and does not seem to follow given numbers.  Please explain.





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