Properties: 2736

Find four numbers whose sum is 48 and which have the following properties: if we subtract 3 from the first, add 3 to the second, multiply the third by three, and divide the fourth by three, we get the same result.

Final Answer:

a =  12
b =  6
c =  3
d =  27

Step-by-step explanation:

a+b+c+d=48 a3 = b+3 b+3 = 3c 3c = d/3  b=a6 c = b/3+1 d = 9c  a+b+c+d=48 a+(a6)+(b/3+1)+9c=48 a+(a6)+((a6)/3+1)+9c=48  a+(a6)+((a6)/3+1)+9((a6)/3+1)=48  a+(a6)+((a6)/3+1)+9 ((a6)/3+1)=48  16a=192  a=16192=12  a=12
b=a6=126=6
c=b/3+1=6/3+1=3
d=9 c=9 3=27



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