Square - increased perimeter

How many times is increased perimeter of the square, where its sides increases by 150%?

If the perimeter of square will increase twice, how much% increases the content area of the square?

Correct result:

n =  0
p2 =  300 %

Solution:

a1=1 a2=a1+1.50 a1=1+1.50 1=52=2.5 o1=4 a1=4 1=4 o2=4 a2=4 2.5=10 n=o2/o1=10/4=52=2.5=0
p2=(2212)/12 100=300%



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