# Perimeter of circle

Calculate the circumference of described circle to the triangle with sides 9,12,15 cm.

Correct result:

o =  47.124 cm

#### Solution:

$c=15 \ \\ c^2=a^2 +b^2 \ \\ 15^2=12^2+9^2 \ \\ \ \\ D=c=15 \ \text{cm} \ \\ \ \\ o=\pi \cdot \ D=3.1416 \cdot \ 15=47.124 \ \text{cm}$

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