To prepare stew for 10 loggers we need: 2.5 kg of potatoes, 0.8 kg of meat, 18 dag of flour, 30 dag onion and 1 bread. What is the required amount of raw materials for 50 participants camps where loggers eats 1.5 times more than a participant of the camp?

Correct answer:

a =  0 kg
b =  2.6667 kg
c =  0.6 kg
d =  1 kg
e =  3.3333

Step-by-step explanation:

k=50/10/1.5=1033.3333 a=k 2.5=3.3333 2.5=2538.3333=0 kg
b=k 0.8=2.6667 kg
d=k 30/100=1 kg
e=k 1=3.3333

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