Decompose

Decompose into primes and find the smallest common multiple n of (16,20) and the largest common divisor D of the pair of numbers (140,100)

Correct result:

n =  80
D =  20

Solution:

$$\begin{gathered} 16=2^4 \\ 20=2^2\cdot 5 \\ LCM(16,20)=2^4\cdot 5=80 \\ n=LCM(16,20)=80 \end{gathered}$$

$$\begin{gathered} 140=2^2\cdot 5\cdot 7 \\ 100=2^2\cdot 5^2 \\ \text{GCD}(140,100)=2^2\cdot 5=20 \\ D=GCD(140,100)=20 \end{gathered}$$

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