# Coordinates of the intersection of the diagonals

In the rectangular coordinate system, a rectangle ABCD is drawn. The vertices of the rectangle are determined by these coordinates
A = (2.2)
B = (8.2)
C = (8.6)
D = (2.6)

Find the coordinates of the intersection of the diagonals of the ABCD rectangle

Correct result:

x =  5
y =  4

#### Solution:

$y=\frac{{A}_{1}+{C}_{1}}{2}=\frac{2+6}{2}=4$

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