Triangle perimeter

The right triangle has squares in the ratio of 5:12, and the circumscribed circle diameter is 26 cm. Determine its perimeter.

Final Answer:

o =  60 cm

Step-by-step explanation:

D=26 cm c=D=26 cm  c2 = a2+b2 c2 = (5k)2+(12k)2 c2 = 25k2+122k2  k=c2/(52+122)=262/(52+122)=2  a=5 k=5 2=10 cm b=12 k=12 2=24 cm o=a+b+c=10+24+26=60 cm



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