A cliff

A line from the top of a cliff to the ground passes just over the top of a pole 5 ft high and meets the ground at a point 8 ft from the base of the pole. If the point is 93 ft from the base of the​ cliff, how high is the​ cliff?

Correct result:

x =  58.125 ft

Solution:

$$\begin{gathered} x:93=5:8=0.625 \\ x=93\cdot {\displaystyle \frac{5}{8}}={\displaystyle \frac{465}{8}}={\displaystyle \frac{465}{8}}\text{ ft}=58.125\text{ ft} \end{gathered}$$

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