Speedboat 3189

At 12:15, a train speeding 55km/h left the station. Twelve minutes later, an 80km/h speedboat set off behind the train. What time does the express train catch up? How far from the station?

Result

t = 12:53 hh:mm Wrong answer
s =  35.2 km

Step-by-step explanation:


s=55·(t-(12+15/60))
s = 80·(t-(12+(15+12)/60))

60s-3300t = -40425
60s-4800t = -59760

Row 2 - Row 1 → Row 2
60s-3300t = -40425
-1500t = -19335


t = -19335/-1500 = 12.89
s = -40425+3300t/60 = -40425+3300 · 12.89/60 = 35.2

s = 176/5 = 35.2
t = 1289/100 = 12.89

Our linear equations calculator calculates it.
s=35.2=35.2 km



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