Divisible by nine

How many three-digit natural numbers in total are divisible without a remainder by the number 9?

Correct answer:

n =  100

Step-by-step explanation:

n1=108 c1=1+0+8=9 n2=999 c2=9+9+9=27  n=(n2−n1)/9+1=(999−108)/9+1=100

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