Divisible 72004

Find the natural number between the numbers 70 and 80 divisible without the remainder 5, 3, 15, and 25.

Correct answer:

x =  75

Step-by-step explanation:

3 ...  prime number 5 ...  prime number 15=35 25=52 LCM(3,5,15,25)=352=75  d=LCM(3,5,15,25)=75 70<x<80  k1=70/d=70/75=15140.9333 k2=80/d=80/75=1516=11511.0667  x=[k1] d=[0.9333] 75=75



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