Gasoline tank cylindrical

What is the inner diameter of the tank, which is 8 m long and contains 40 cubic cubic meters of gasoline?

Result

D =  2.523 m

Solution:

V=40 m3 l=8 m S=V/l=40/8=5 m2 S=πD2/4 D=4⋅ S/π=4⋅ 5/3.1416≐2.5231=2.523  m V = 40 \ m^3 \ \\ l = 8 \ m \ \\ S = V/l = 40/8 = 5 \ m^2 \ \\ S = \pi D^2/4 \ \\ D = \sqrt{ 4 \cdot \ S/ \pi } = \sqrt{ 4 \cdot \ 5/ 3.1416 } \doteq 2.5231 = 2.523 \ \text{ m }

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