Water tank

The water tank has a cylindrical shape with a base diameter of 4.2 m and is 80 cm deep. How many minutes will take fill it 10 cm below the edge of the tank if water flowing 2 liters per second?

Result

t =  80.817 min

Solution:

D=42 dm h=(80−10)/10=7 dm r=D/2=42/2=21 dm V=π⋅ r2⋅ h=3.1416⋅ 212⋅ 7≐9698.0965 dm3 v=2⋅ 60=120 l/min t=V/v=9698.0965/120≐80.8175=80.817  min D = 42 \ dm \ \\ h = (80-10)/10 = 7 \ dm \ \\ r = D/2 = 42/2 = 21 \ dm \ \\ V = \pi \cdot \ r^2 \cdot \ h = 3.1416 \cdot \ 21^2 \cdot \ 7 \doteq 9698.0965 \ dm^3 \ \\ v = 2 \cdot \ 60 = 120 \ l/min \ \\ t = V/v = 9698.0965/120 \doteq 80.8175 = 80.817 \ \text{ min }

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