Round up - fountain

A fountain, cylindrical in shape with a base diameter of 2 m, is 25 cm deep. How many litres of water can it hold?
Round the result to the nearest whole number.

Final Answer:

V =  8 hl

Step-by-step explanation:

$$\begin{gathered} d=2\text{m} \\ h=25\text{cm}\to \text{m}=25:100\text{m}=0.25\text{m} \\ r=d/2=2/2=1\text{m} \\ {S}_1=\pi \cdot r^2=3.1416\cdot 1^2\doteq 3.1416{\text{m}}^2 \\ {V}_1=S_1\cdot h=3.1416\cdot 0.25\doteq 0.7854{\text{m}}^3 \\ V=V_1\to \text{hl}=V_1\cdot 10\text{hl}=0.7854\cdot 10\text{hl}=8\text{hl}=8\text{hl} \end{gathered}$$

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