The projectile

The projectile was fired horizontally from a height of h = 25 meters above the ground at a speed of v0 = 250 m/s.
Find the range and flight time of the projectile.

Correct result:

x =  0.5644 km
t =  2.2576 s

Solution:

$$\begin{gathered} g=9.81{\text{m/s}}^2 \\ h=25\text{ m } \\ {v}_0=250\text{ m/s } \\ t=\sqrt{{\displaystyle \frac{2\cdot h}{g}}}=\sqrt{{\displaystyle \frac{2\cdot 25}{9.81}}}\doteq 2.2576\text{ s } \\ {x}_1=v_0\cdot t=250\cdot 2.2576\doteq 564.4046\text{ m } \\ x=x_1\to \text{ km}=x_1\mathrm{/}1000\text{ km}=564.4046\mathrm{/}1000\text{ km}=0.564\text{ km}=0.5644\text{ km} \end{gathered}$$

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